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- /*
- * Copyright (C) 1993, 1994, 1995, 1996, 1997 Free Software Foundation, Inc.
- * This file is part of the GNU C Library.
- * Contributed by Paul Eggert (eggert@twinsun.com).
- *
- * The GNU C Library is free software; you can redistribute it and/or
- * modify it under the terms of the GNU Library General Public License as
- * published by the Free Software Foundation; either version 2 of the
- * License, or (at your option) any later version.
- *
- * The GNU C Library is distributed in the hope that it will be useful,
- * but WITHOUT ANY WARRANTY; without even the implied warranty of
- * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
- * Library General Public License for more details.
- *
- * You should have received a copy of the GNU Library General Public
- * License along with the GNU C Library; see the file COPYING.LIB. If not,
- * write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,
- * Boston, MA 02111-1307, USA.
- */
- /*
- * Converts the calendar time to broken-down time representation
- * Based on code from glibc-2.6
- *
- * 2009-7-14:
- * Moved from glibc-2.6 to kernel by Zhaolei<zhaolei@cn.fujitsu.com>
- */
- #include <linux/time.h>
- #include <linux/module.h>
- /*
- * Nonzero if YEAR is a leap year (every 4 years,
- * except every 100th isn't, and every 400th is).
- */
- static int __isleap(long year)
- {
- return (year) % 4 == 0 && ((year) % 100 != 0 || (year) % 400 == 0);
- }
- /* do a mathdiv for long type */
- static long math_div(long a, long b)
- {
- return a / b - (a % b < 0);
- }
- /* How many leap years between y1 and y2, y1 must less or equal to y2 */
- static long leaps_between(long y1, long y2)
- {
- long leaps1 = math_div(y1 - 1, 4) - math_div(y1 - 1, 100)
- + math_div(y1 - 1, 400);
- long leaps2 = math_div(y2 - 1, 4) - math_div(y2 - 1, 100)
- + math_div(y2 - 1, 400);
- return leaps2 - leaps1;
- }
- /* How many days come before each month (0-12). */
- static const unsigned short __mon_yday[2][13] = {
- /* Normal years. */
- {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365},
- /* Leap years. */
- {0, 31, 60, 91, 121, 152, 182, 213, 244, 274, 305, 335, 366}
- };
- #define SECS_PER_HOUR (60 * 60)
- #define SECS_PER_DAY (SECS_PER_HOUR * 24)
- /**
- * time_to_tm - converts the calendar time to local broken-down time
- *
- * @totalsecs the number of seconds elapsed since 00:00:00 on January 1, 1970,
- * Coordinated Universal Time (UTC).
- * @offset offset seconds adding to totalsecs.
- * @result pointer to struct tm variable to receive broken-down time
- */
- void time_to_tm(time_t totalsecs, int offset, struct tm *result)
- {
- long days, rem, y;
- const unsigned short *ip;
- days = totalsecs / SECS_PER_DAY;
- rem = totalsecs % SECS_PER_DAY;
- rem += offset;
- while (rem < 0) {
- rem += SECS_PER_DAY;
- --days;
- }
- while (rem >= SECS_PER_DAY) {
- rem -= SECS_PER_DAY;
- ++days;
- }
- result->tm_hour = rem / SECS_PER_HOUR;
- rem %= SECS_PER_HOUR;
- result->tm_min = rem / 60;
- result->tm_sec = rem % 60;
- /* January 1, 1970 was a Thursday. */
- result->tm_wday = (4 + days) % 7;
- if (result->tm_wday < 0)
- result->tm_wday += 7;
- y = 1970;
- while (days < 0 || days >= (__isleap(y) ? 366 : 365)) {
- /* Guess a corrected year, assuming 365 days per year. */
- long yg = y + math_div(days, 365);
- /* Adjust DAYS and Y to match the guessed year. */
- days -= (yg - y) * 365 + leaps_between(y, yg);
- y = yg;
- }
- result->tm_year = y - 1900;
- result->tm_yday = days;
- ip = __mon_yday[__isleap(y)];
- for (y = 11; days < ip[y]; y--)
- continue;
- days -= ip[y];
- result->tm_mon = y;
- result->tm_mday = days + 1;
- }
- EXPORT_SYMBOL(time_to_tm);
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